12 February 2011

Help!

I have a thing for helpmates. Every now and then, I post some nice finds. Enjoy!

  1David Bevan  
The Problemist 11/2003
[8/4k3/r7/4K3/5N2/8/8/8]
  h#5      2.1...(2+2)  

  2A. Henkel  
The Problemist FCS 07/2003
[8/2q1p3/8/1k6/6PK/8/8/8]
  h#4(2+3)  
a) Diagram
b) wQc7

Solutions:
1 I) 1. Kd7 Nd5 2. Kc6 Ke6 3. Kb7+ Kd7 4. Ka8 Kc8 5. Ra7 Nb6#
II) 1. Rh6 Kd5 2. Kf6 Kd6 3. Kg7+ Ke7 4. Kh8 Kf8 5. Rh7 Ng6#
2 a) 1. Kc6 g5 2. Kd7 g6 3. Ke8 g7 4. Qd7 g8=Q#
b) 1. e5 Qf7 2. Kc5 Kg3 3. Kd4 Kf2 4. Ke4 Qc4#

No comments: